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The lines parallel to the normal to the curve `x y=1`is/are`3x+4y+5=0`(b) `3x-4y+5=0``4x+3y+5=0`(d) `3y-4x+5=0`A. `3x+4y+5=0`B. `3x-4y+5=0`C. `4x+3y+5=0`D. `3y-4x+5=0` |
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Answer» Correct Answer - B::D Differentiating xy = 1 w.r.t. x, we have `(dy)/(dx)=-(1)/(x^(2))lt0` Hence, the slope of normal at any point `P(x_(1),y_(1))` is `x_(1)^(2)gt0`. Therefore, the slope of normal must always be positive. Hence, the possible lines are (2) and (4). |
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