InterviewSolution
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InterviewSolution
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The magnitude `(` but not the sign `)` of the standard reduction potentials of two metals `X` and `Y` are `:` `Y^(2)+2e^(-) rarr Y |E_(1)^(c-)|=0.34V` `X^(2)+2e^(-) rarr X |E_(2)^(c-)|=0.25V` When the two half cells of `X` and `Y `are connected to construct a cell, eletrons flow from `X` to `Y`. When `X` is connected to a standard hydrogen electrode `(SHE)`,electrons flow from `X` to `SHE`. Given the following half cell `: YI+e^(-) rarr Y-I^(c-): " "E^(c-)=-0.27 V` Solubility product of the iodide salt `YI` isA. `2 xx 10^(-3)`B. `2 xx 10^(-12)`C. `10^(-15)`D. `6.8 xx 10^(-16)` |
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Answer» Correct Answer - C When connected, electron flow from `X` to `Y` means, `E_(Y^(2+)//Y)^(@) gt E_(X^(2+)//X)^(@)` and when `X` is connected to `SHF`, e flow from `X` to `SHE` means. `E_(X^(2+)//X)^(@)` `{:(YI +e^(-) rarr Y +I^(-)E^(@) =- 0.37 V),(Y rarr Y^(+) +e^(-) " "E^(@) = - 0.53 V):}/(Yi hArr Y^(+) +I^(-) " "E^(@) =- 0.90 V)` So, `E^(@) = (0.06)/(n) log K_(p)` `- 0.90 = (0.06)/(1) log K_(sp)` `log K_(sp) =- 15` `K_(sp) = 10^(-15)` |
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