The maximum and minimum distance of a comet from the sun are 1.4xx10^(12)m and 7xx10^(10)m . If its velocity nearest to the sun is 6xx10^(4)ms^(-1), then what is the velocity at the farthest position ? Assume the path of the comet as circular.

The maximum and minimum distance of a comet from the sun are 1.4xx10^(

1.	The maximum and minimum distance of a comet from the sun are 1.4xx10^(12)m and 7xx10^(10)m . If its velocity nearest to the sun is 6xx10^(4)ms^(-1), then what is the velocity at the farthest position ? Assume the path of the comet as circular.
Answer» Solution :`I_1=1.4xx10^(12)m,d_2=7xx10^(10)m` `v_1=6xx10^(4)MS^(-1),v_2`=? Since ANGULAR momentum is CONSERVED `m_pr_pv_p=m_pr_av_a` `(v_p)/(v_A)=(r_A)/(r_p)`i.e, `(6xx10^4)/(V_a)=(7xx10^(10))/(1.4xx10^(12))` i.e `v_A=(6xx10^4xx1.4xx10^(12))/(7xx10^(10))"":." "v_A=1.2xx10^(6)ms^(-1)`