The maximum and minimum distance of a comet from the sun are 1.4xx10^(12)m and 7xx10^(10)m . If its velocity nearest to the sun is 6xx10^(4)ms^(-1), then what is the velocity at the farthest position ? Assume the path of the comet as circular.

The maximum and minimum distance of a comet from the sun are 1.4xx10^(

1.	The maximum and minimum distance of a comet from the sun are 1.4xx10^(12)m and 7xx10^(10)m . If its velocity nearest to the sun is 6xx10^(4)ms^(-1), then what is the velocity at the farthest position ? Assume the path of the comet as circular.
Answer» <html><body><p></p>Solution :`I_1=1.4xx10^(<a href="https://interviewquestions.tuteehub.com/tag/12-269062" style="font-weight:bold;" target="_blank" title="Click to know more about 12">12</a>)m,d_2=7xx10^(10)m` <br/> `v_1=6xx10^(4)<a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(-1),v_2`=? <br/> Since <a href="https://interviewquestions.tuteehub.com/tag/angular-11524" style="font-weight:bold;" target="_blank" title="Click to know more about ANGULAR">ANGULAR</a> momentum is <a href="https://interviewquestions.tuteehub.com/tag/conserved-2539138" style="font-weight:bold;" target="_blank" title="Click to know more about CONSERVED">CONSERVED</a> <br/> `m_pr_pv_p=m_pr_av_a` <br/> `(v_p)/(v_A)=(r_A)/(r_p)`i.e, `(6xx10^4)/(V_a)=(7xx10^(10))/(1.4xx10^(12))` <br/> i.e `v_A=(6xx10^4xx1.4xx10^(12))/(7xx10^(10))"":." "v_A=1.2xx10^(6)ms^(-1)`</body></html>