InterviewSolution
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InterviewSolution
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The maximum velocity and the maximum acceleration of a body moving in a simple harmonic oscillator are 2 m/s and` 4 m//s^(2)`. Then angular velocity will beA. 3 `rads^(-1)`B. 0.5 `rads^(-1)`C. 1 `rads^(-1)`D. 2 `rads^(-1)` |
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Answer» Correct Answer - D At extreme position, displacement of particle executing SHM is maximum. Maximum velocity of particle executing SHM is given by `therefore" "v_(max) = omega A` Maximum acceleration of particle executing SHM is given by, `a =-omega^(2)A or a_(max)=|A|=omega^(2)A` As `a_(max)=(Aomega)omega=v_(max).omega` `therefore" "omega=(a_(max))/(v_(max))=(4)/(2)=2 rads^(-1)` |
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