InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
The molar conducatance of `Ba^(2+)` and `Cl^(-)` are `127` and `76 ohm^(-1) cm^(-1) mol^(-1)` respectively at infinite dilution. The equivalent conductance of `BaCl_(2)` at infinte dilution will beA. `139.52`B. `203`C. `279`D. `101.5` |
|
Answer» Correct Answer - A According to Kohlrausch law of independent migration of ions, limiting equivalent conductance of an electrolyte can be represented as the sum of the individual contributions of the anion and cation of the electrolyte, Thus `Lambda_(eq.)^(@)(BaCl_(2))=lamda_(eq.)^(@)(Ba^(2+))+lamda_(eq.)^(@)(Cl^(-))` Since `Ba^(+)` is divalent while `Cl^(-)` is univalent, `lamda_(eq.)^(@)(Ba^(2+)) = 1//2` `lamda_(m)^(@)(Ba^(2+)` while `lamda_(eq.)^(@)(Cl^(-)) = lamda_(m)^(@)(Cl^(-))`. Thus `lamda_(eq.)^(@)(BaCl^(2)) = ((127)/(2)+76) ohm^(-1) cm^(-1) eq^(-1)` `=139.5 ohm^(-1) cm^(-1) eq^(-1)` |
|