The molar conductivities `Lambda_(NaOAc)^@` and `Lambda_(HCI)^@` at infinite dilution is watter at `25^@C` are `91.0` and `426.2 S cm^@ //`mol respectively. To calculate `Lambda_(HOAc,)^2` the additional value required is:A. `Lambda_(H_(2)O)^(@)`B. `Lambda_(KCl)^(@)`C. `Lambda_(NaOH)^(@)`D. `Lambda_(NaCl)^(@)`

The molar conductivities `Lambda_(NaOAc)^@` and `Lambda_(HCI)^@` at in

1.	The molar conductivities `Lambda_(NaOAc)^@` and `Lambda_(HCI)^@` at infinite dilution is watter at `25^@C` are `91.0` and `426.2 S cm^@ //`mol respectively. To calculate `Lambda_(HOAc,)^2` the additional value required is:A. `Lambda_(H_(2)O)^(@)`B. `Lambda_(KCl)^(@)`C. `Lambda_(NaOH)^(@)`D. `Lambda_(NaCl)^(@)`
Answer» Correct Answer - D According to Kohlrausch law : `Lambda_(HOAc)^(@) = Lambda_(NaOAC)^(@) + Lambda_(HCl)^(@) - Lambda_(NaCl)^(@)`

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Define molar conductivity of a solution and explain how molar conductivity changes with change in concentration of a solution for a weak and a strong electrolyte.
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What are elementary reactions ?

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