1.

The molar heat capacity of a gas at constant volume is found to be `5 cal mol^(-1) K^(-1)`. Find the ratio`gamma = C_p/C_v` for the gas. The gas constant `R=2 cal mol^(-1) K^(-1).

Answer» We have `C_v = 5 cal mol^(-1) K^(-1).
Thus. `C_p = C_v + R = 5 cal mol^(-1) K^(-1) + cal mol^(-1) = 7 cal mol^(-1) K^(-1)`
or, C_p / C_v = 7/5 = 1.4`


Discussion

No Comment Found

Related InterviewSolutions