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The mole of fraction of nitrogen, in a mixture of 7 g of `N_(2)` and 16 g of `O_(2)` isA. 0.5B. 0.75C. 0.66D. 0.33 |
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Answer» Correct Answer - D Moles of `N_(2) = 7/28=0.25` and Moles of `O_(2) = 16/32 = 0.5` Mole fraction of `N_(2) = 0.25/(0.25 + 0.5)=0.33` |
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