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The momentum of a moving particle is vectorially given a, `vecp=p_(0)(costhati+sinthatj)`where `t` stands for time. Choose the correct option:A. The applied force is constant.B. The momentum is constant.C. The applied force always remains perpendicular to the momentum.D. The applied force is always parallel to the momentum. |
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Answer» Correct Answer - C `p=p_(0)(costhati+sinthatj)` `vecF=(vec(dp))/(dt)=p_(0)[-sinthati+costhatj]` Both`vecp` and `vecF` are function of time. So none of the is constant. We see that `vecF.vecp=0`, so `vecF_|_^(r)vecp` |
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