The normal length of a steel spring is 8cm. Keeping one end of the spring fixed at a point, if a weight is attached to the other end, its length becomes 14 cm. The weight is pulled down slightly and then released. Find the time period of oscillation of the spring?

The normal length of a steel spring is 8cm. Keeping one end of the spr

1.	The normal length of a steel spring is 8cm. Keeping one end of the spring fixed at a point, if a weight is attached to the other end, its length becomes 14 cm. The weight is pulled down slightly and then released. Find the time period of oscillation of the spring?
Answer» <html><body><p></p>Solution :Increase in <a href="https://interviewquestions.tuteehub.com/tag/length-1071524" style="font-weight:bold;" target="_blank" title="Click to know more about LENGTH">LENGTH</a> of the spring for the mass m is, <br/> l = 14 - 8 = 6 cm. <br/> So, <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> constant k (force required for a unit increase in length) = `(mg)/6"<a href="https://interviewquestions.tuteehub.com/tag/dyn-2596635" style="font-weight:bold;" target="_blank" title="Click to know more about DYN">DYN</a>"*cm^(-1)`. <br/> Time <a href="https://interviewquestions.tuteehub.com/tag/period-1151023" style="font-weight:bold;" target="_blank" title="Click to know more about PERIOD">PERIOD</a>, `T=2pisqrt(m/k)=2pisqrt(m/((mg)/6))` <br/> = `2pisqrt(6/g)=2xx3.14xxsqrt(6/980)=0.49s`.</body></html>