1.

The number of atoms is 100 g of a fcc crystal with density ="10.0 g/cm"^3` and cell edge equal to 200 pm is equal toA. `5xx10^24`B. `5xx10^25`C. `6xx10^23`D. `2xx10^25`

Answer» Correct Answer - A
`rho=(ZxxM)/(a^3xx10^(-30)xxN_0)` or `M=(10xx(200)^3xx10^(-30)xx6xx10^23)/4=12`
Thus, 12 g contain=`N_0=6xx10^23` atoms
`therefore` 100 g will contain `=(6xx10^23)/12xx100=5xx10^24`


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