1.

The number of different ways in which 8 persons can stand in a row so that between two particular persons A and B there are always two persons, is A. 60 × 5! B. 15 × 4! × 5! C. 4! × 5! D. none of these

Answer»

Option : (D)

As, It is required that, two particular persons A and B there are always two persons so, let us consider this arrangement be "AxxB" and consider it as a single object. 

So, 

We are left with, 4 persons and an object, i.e. total 5 objects. 

Now, 

This 5 objects can be arranged in 5! ways. 

Again, 

The two 'x' are to be filled with 2 persons from 6 persons, this can be done in 6P2 = 30 ways. 

Two persons ‘A’ and ‘B’ can be arranged in 2! = 2 ways. 

So, 

The total number of different ways in which 8 persons can stand in a row so that between two particular persons A and B there are always two persons, is = 5! x 30 x 2

= 5! x 60.



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