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The number of electrons delivered at the cathode during electrolysis by a current of `1` ampere in 60 seconds is (charger on electron `= 1.60 xx 10^(-19)C`)A. `7.48xx 10^23`B. `6xx10^23`C. `6xx10^20`D. `3.75xx10^20` |
Answer» Correct Answer - D `(W)/(E)=(1xx60)/(96500)` `=(6)/(9650)=`no. of mole `e^(-)` no. of `e^(-)=(6)/(9650)xx6.02xx10^(23)` `=3.75xx10^(20)` |
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