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The number of electrons delivered at the cathode during electrolysis by a current of `1` ampere in 60 seconds is (charger on electron `= 1.60 xx 10^(-19)C`)A. `6 xx 10^(23)`B. `6 xx 10^(20)`C. `3.75 xx 10^(20)`D. `7.48 xx 10^(23)` |
Answer» Correct Answer - C Number of electrons `= ("Total charge delivered")/("charge on single electron")` `= (1A)(60 s)/(1.60 xx 10^(-19) C//e^(-)), (Q=It)` `= 37.5 xx 10^(19)` electrons `= 3.75 xx 10^(20)` electrons |
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