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The number of moles of ferrus oxalate oxidised by one mole of `KMnO_(4)` in acidic medium is:A. `5//2`B. `2//5`C. `3//5`D. `5//3`

Answer» Correct Answer - D
Eq. of `1FeC_(2)O_(4)`=Eq. of `KMnO_(4)`
moles of `FeC_(2)O_(4)xx3` = moles of `KMnO_(4)xx5`
so, moles of `FeC_(2)O_(4)=5//3`


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