The oxidation number of `S` in `Na_(2)S_(4)O_(6)` isA. `+2.5`B. `+2 and +3` (two S have +2 and other two have +3)C. `+2 and +3` (three S have +2 and one S has +3)D. `+5 and 0` (two S have +5 and the other two have 0)

The oxidation number of `S` in `Na_(2)S_(4)O_(6)` isA. `+2.5`B. `+2 an

1.	The oxidation number of `S` in `Na_(2)S_(4)O_(6)` isA. `+2.5`B. `+2 and +3` (two S have +2 and other two have +3)C. `+2 and +3` (three S have +2 and one S has +3)D. `+5 and 0` (two S have +5 and the other two have 0)
Answer» Correct Answer - D The structural formula of `Na_(2)S_(4)O_(6)` (sodium tetrathionate) is as follows `{:(" O O"),(" \|\| \|\|"),(Na^(+)O^(-)-S-S-S-S-O^(-)Na^(+)),(" \|\| \|\|"),(" O O"):}` The O.N of the two central sulphur atoms which are linked only to each other i.e., -S-S- is zero. Let the O.N of the other two sulphur atoms be x each. Here, O.N. of O is -2 and O.N. of tetrathionate ion = -2 `:. 6xx(-2)+2xx0+2xx x=-2` `-12+2x=-2` `x=5` Thus, two S atoms in `Na_(2)S_(4)O_(6)` have O.N. of zero each, while the other two S atoms have O.N of 5 each.

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The oxidation number of `S` in `Na_(2)S_(4)O_(6)` isA. `+2.5`B. `+2 and +3` (two S have +2 and other two have +3)C. `+2 and +3` (three S have +2 and one S has +3)D. `+5 and 0` (two S have +5 and the other two have 0)

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