The path of a projectile is given by the equation y = ax - bx^2 , where a and b are constants and x and y are respectively horizontal and vertical distances of projectile from the point of projection. The maximum height attained by the projectile and the angle of projection are respectively

The path of a projectile is given by the equation y = ax - bx^2 , wher

1.	The path of a projectile is given by the equation y = ax - bx^2 , where a and b are constants and x and y are respectively horizontal and vertical distances of projectile from the point of projection. The maximum height attained by the projectile and the angle of projection are respectively
Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/2a-300249" style="font-weight:bold;" target="_blank" title="Click to know more about 2A">2A</a>^2)/(b), <a href="https://interviewquestions.tuteehub.com/tag/tan-1238781" style="font-weight:bold;" target="_blank" title="Click to know more about TAN">TAN</a>^(-1)(a)`<br/>`(b^2)/(2a) ,tan^(-1) (b)` <br/>`(a^2)/(b) ,tan^(-1) (<a href="https://interviewquestions.tuteehub.com/tag/2b-300274" style="font-weight:bold;" target="_blank" title="Click to know more about 2B">2B</a>)`<br/>`(a^2)/(4b), tan^(-1) (a)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html>