The path of a projectile is given by the equation y = ax - bx^2 , where a and b are constants and x and y are respectively horizontal and vertical distances of projectile from the point of projection. The maximum height attained by the projectile and the angle of projection are respectively

The path of a projectile is given by the equation y = ax - bx^2 , wher

1.	The path of a projectile is given by the equation y = ax - bx^2 , where a and b are constants and x and y are respectively horizontal and vertical distances of projectile from the point of projection. The maximum height attained by the projectile and the angle of projection are respectively
Answer» `(2A^2)/(b), TAN^(-1)(a)` `(b^2)/(2a) ,tan^(-1) (b)` `(a^2)/(b) ,tan^(-1) (2B)` `(a^2)/(4b), tan^(-1) (a)` ANSWER :D