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The period of oscillation of a mass m suspended from a spring of negligible mass is T. If along with it another mass m is also suspended the period of oscillation will now be……..

Answer» <html><body><p>`T`<br/>`(T)/(sqrt(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/2t-301164" style="font-weight:bold;" target="_blank" title="Click to know more about 2T">2T</a>`<br/>`sqrt(2)T`</p>Solution :In first <a href="https://interviewquestions.tuteehub.com/tag/case-910082" style="font-weight:bold;" target="_blank" title="Click to know more about CASE">CASE</a> `T= 2pi sqrt((M)/(k))` <br/> In second case `T. = 2pi sqrt((M+M)/(k))= 2pi sqrt((2M)/(k))` <br/> `therefore (T.)/(T)= sqrt(2)` <br/> `therefore T. = sqrt(2)T`.</body></html>


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