1.

The period of oscillation of a mass m suspended from a spring of negligible mass is T. If along with it another mass m is also suspended the period of oscillation will now be……..

Answer»

`T`
`(T)/(sqrt(2))`
`2T`
`sqrt(2)T`

Solution :In first CASE `T= 2pi sqrt((M)/(k))`
In second case `T. = 2pi sqrt((M+M)/(k))= 2pi sqrt((2M)/(k))`
`therefore (T.)/(T)= sqrt(2)`
`therefore T. = sqrt(2)T`.


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