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The period of oscillation of a mass m suspended from a spring of negligible mass is T. If along with it another mass m is also suspended the period of oscillation will now be…….. |
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Answer» `T` In second case `T. = 2pi sqrt((M+M)/(k))= 2pi sqrt((2M)/(k))` `therefore (T.)/(T)= sqrt(2)` `therefore T. = sqrt(2)T`. |
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