The periodic time of simple pendulum is T=2pi sqrt((l)/(g)). The length (l) of the pendulum is about 100 cm measured with 1mm accuracy. The periodic time is about 2s. When 100 oscillations are measured by a stop watch having the least count 0.1 second. Calcaulte the percentage error in measurement of g.

The periodic time of simple pendulum is T=2pi sqrt((l)/(g)). The lengt

1.	The periodic time of simple pendulum is T=2pi sqrt((l)/(g)). The length (l) of the pendulum is about 100 cm measured with 1mm accuracy. The periodic time is about 2s. When 100 oscillations are measured by a stop watch having the least count 0.1 second. Calcaulte the percentage error in measurement of g.
Answer» <html><body><p>`0.1%`<br/>0.01<br/>`0.<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>%`<br/>`0.8%`</p>Solution :`T=nT=100xx2=200s and Deltat=0.1s` <br/> `T=2pisqrt((l)/(g))"":.T=(4pi^(2)l)/(g)` <br/> `:.g=(4pi^(2)l)/(T^(2))` <br/> `4pi^(2)`= <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a> =dimensionless <br/> `:.(Deltag)/(g)=(Deltal)/(l)+(2DeltaT)/(T)` <br/> `=(Deltal)/(l)xx100+2(Deltat)/(t)xx100` <br/> `=[(0.1)/(<a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a>)xx100]+[2xx(0.1)/(2xx100)xx100]` <br/> `=0.1+0.1=0.2%`</body></html>