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The pH of 0.05 M solution of dibasic acid is : (a) +1 (b) -1 (c) +2 (d) -2 |
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Answer» (a) +1 0.05 M dibasic acid gives 0.1 M \(H^+\) ions. Therefore, \(P^H=-\log\,[\,H^+]=-\log 10^{-1}\) \(P^H=+1\) Option : (a) +1 |
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