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The `pH` of milk, black coffee, tomato juice, lemon juice and egg white are `6.8, 5.0, 4.2, 2.2` and `7.8` respectively. Calculate corresponding hydrogen ion concentration in each. |
Answer» `(a) [H^(+)]` of milk `pH =6.8 " or " -log [H^(+)] =6.8 " or " log [H^(+)] =- 6.8` `[H^(+)] = "Antilog " (-6.80) = " Antilog " (bar(7).20) =1.58 xx 10^(-7) M` `(b) [H^(+)]` of block coffe `pH =5.0 " or " - log [H^(+)] =5.0 " or " log [H^(+)] =- 5.0` `[H^(+)] = "Antilog " (-5.0) = " Antilog " bar(5) = 10^(-5) M` (c) `[H^(+)]` of tomato juice `pH =4.2 " or " - log [H^(+)] =4.2 " or " log [H^(+)] =- 4.2` `[H^(+)] = "Antilog " (-4.2) = " Antilog" (bar(5).80) =6.31 xx 10^(-5)M` (d) `[H^(+)]` of lemon juice `pH =2.2 " or " - log [H^(+)] =2.2 " or " log [H^(+)] =- 2.2` `[H^(+)] = " Antilog " (-2.2) = " Antilog" (bar(3).80) =6.310 xx 10^(-3)M` `(e) [H^(+)]` of egg white `pH =7.8 " or " - log [H^(+)] =7.8 " or " log [H^(+)] =- 7.8` `[H^(+)] = " Antilog" (-7.8) = " Antilog " (bar(8).20) = 1.58 xx 10^(-8) M` |
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