The position of a particle moving along a straight line is given by x =2 - 5t + t ^(3). Find the acceleration of the particle at t =2 s. (x is metere).

The position of a particle moving along a straight line is given by x

1.	The position of a particle moving along a straight line is given by x =2 - 5t + t ^(3). Find the acceleration of the particle at t =2 s. (x is metere).
Answer» <html><body><p></p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a> (t) = <a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> - 5t + t ^(3)` is given, <br/> `therefore <a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a> = (dx)/(dt) = (d)/(dt) [2- 5t +t ^(3)]` <br/> `therefore v =-5 + <a href="https://interviewquestions.tuteehub.com/tag/3t-311358" style="font-weight:bold;" target="_blank" title="Click to know more about 3T">3T</a> ^(2)` and <a href="https://interviewquestions.tuteehub.com/tag/acceleration-13745" style="font-weight:bold;" target="_blank" title="Click to know more about ACCELERATION">ACCELERATION</a> <br/> `a = (dv)/(dt) = (d)/(dt) [-5 + 3t ^(2) ] = 6t` acceleration at 2s, `a = 6 xx 2 =12 ms ^(-2)`</body></html>