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The position of the particle is represented by y = ut-1/2 "gt"^2 (a) What is the force acting on the particle? (b) What is the momentum of the particle? |
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Answer» Solution :To find the force, we need to find the ACCELERATION experienced by the particle. The acceleration is given by `a= (d^2 y)/(dt^2) " or" a = (dv)/(dt)` Here v= velocity of the particle in y direction ` v = (dy)/(dt) = u - "gt"` The momentum of the particle ` = mv = m ( u - "gt" )` `a = (dv)/(dt) = - g` The force ACTING on the object is given by F = ma = -mg The negative SIGN implies that the force is acting on the negative y direction. This is exactly the force that acts on the object in projectile motion. |
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