The position of the particle is represented by y = ut-1/2 "gt"^2 (a) What is the force acting on the particle? (b) What is the momentum of the particle?

The position of the particle is represented by y = ut-1/2 "gt"^2 (a) W

1.	The position of the particle is represented by y = ut-1/2 "gt"^2 (a) What is the force acting on the particle? (b) What is the momentum of the particle?
Answer» <html><body><p></p>Solution :To find the force, we need to find the <a href="https://interviewquestions.tuteehub.com/tag/acceleration-13745" style="font-weight:bold;" target="_blank" title="Click to know more about ACCELERATION">ACCELERATION</a> experienced by the particle.<br/>The acceleration is given by `a= (d^2 y)/(dt^2) " or" a = (dv)/(dt)` <br/>Here v= velocity of the particle in y direction ` v = (dy)/(dt) = u - "gt"` <br/>The momentum of the particle ` = mv = m ( u - "gt" )` <br/>`a = (dv)/(dt) = - g` <br/>The force <a href="https://interviewquestions.tuteehub.com/tag/acting-269" style="font-weight:bold;" target="_blank" title="Click to know more about ACTING">ACTING</a> on the object is given by <a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a> = ma = -mg<br/>The negative <a href="https://interviewquestions.tuteehub.com/tag/sign-1207134" style="font-weight:bold;" target="_blank" title="Click to know more about SIGN">SIGN</a> implies that the force is acting on the negative y direction. This is exactly the force that acts on the object in projectile motion.</body></html>