The position vector of a particle is given as →r=(t2−4t+6)^i+(t2)^j. The time after which the velocity vector and acceleration vector becomes perpendicular to each other is equal to

The position vector of a particle is given as →r=(t2−4t+6)^i+(t2)^

1.	The position vector of a particle is given as →r=(t2−4t+6)^i+(t2)^j. The time after which the velocity vector and acceleration vector becomes perpendicular to each other is equal to
Answer» The position vector of a particle is given as $\to r = (t^{2} - 4 t + 6)^i + (t^{2})^j .$ The time after which the velocity vector and acceleration vector becomes perpendicular to each other is equal to

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The position vector of a particle is given as →r=(t2−4t+6)^i+(t2)^j. The time after which the velocity vector and acceleration vector becomes perpendicular to each other is equal to

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