1.

The potential energy of a particle with displacement X is `U(X)`. The motion is simple harmonic, when (K is a positive constant)A. `u=(-kx^(2))/(2)`B. `u=(1)/(2)kx^(2)`C. `u=k`D. `u=kx`

Answer» Correct Answer - B
`P.E.=(1)/(2) m omega^(2)x^(2) " As" (1)/(2) m omega^(2)=`const.
`therefore P.E. prop x^(2)=k x^(2)`


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