The pressure of `H_(2)` required to make the potential of `H_(2)-`electrode zero in pure water at 289K is :A. `10^(-12) atm `B. `10^(-10) atm `C. `10^(-4) atm `D. `10^(-14)atm`

The pressure of `H_(2)` required to make the potential of `H_(2)-`elec

1.	The pressure of `H_(2)` required to make the potential of `H_(2)-`electrode zero in pure water at 289K is :A. `10^(-12) atm `B. `10^(-10) atm `C. `10^(-4) atm `D. `10^(-14)atm`
Answer» Correct Answer - D (d) From the question, we have an equation `2H^(+)+2e^(-) to H_(2)(g)` According to Nernst equation, `E=E^(@)-(0.059)/(2)log""(p_(Hg))/([H^(+)]^(2))` `=0-(0.059)/(2) log""(p_(Hg))/((10^(-7))^(2))" " [:.[H^(+)]=10^(-7)]` `:.` For potential of `H_(2)` electrode to be zero, `p_(H_(2))` should be equal to `[H^(+)]^(2)`,i.e `10^(-14)` atm. `:." " log""(10^(-14))/((10^(-7))^(2))=0`

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The pressure of `H_(2)` required to make the potential of `H_(2)-`electrode zero in pure water at 289K is :A. `10^(-12) atm `B. `10^(-10) atm `C. `10^(-4) atm `D. `10^(-14)atm`

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