The pressure of `H_(2)` required to make the potential of `H_(2)-`electrode zero in pure water at 298K isA. `10^(-14)atm`B. `10^(-12)atm`C. `10^(-10)atm`D. `10^(-4)atm`

The pressure of `H_(2)` required to make the potential of `H_(2)-`elec

1.	The pressure of `H_(2)` required to make the potential of `H_(2)-`electrode zero in pure water at 298K isA. `10^(-14)atm`B. `10^(-12)atm`C. `10^(-10)atm`D. `10^(-4)atm`
Answer» Correct Answer - A `2H^(+)(aq)=2e^(-)toH_(2)(g)` `thereforeE=E^(0)-(0.0591)/(2)"log"(P_(H_(2)))/([H^(+)]^(2))` `0=0-0.295"log"(P_(H_(2)))/((10^(-7))^(2))` `(P_(H_(2)))/((10^(-7))^(2))=1` `P_(H_(2))=10^(-14)atm`

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The pressure of `H_(2)` required to make the potential of `H_(2)-`electrode zero in pure water at 298K isA. `10^(-14)atm`B. `10^(-12)atm`C. `10^(-10)atm`D. `10^(-4)atm`

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