The pressure of `H_(2)` required to make the potential of `H_(2)`- electrode zero in pure water at 298 K isA. `10^(-10)m`B. `10^(-4)atm`C. `10^(-14)atm`D. `10^(-12)atm`

The pressure of `H_(2)` required to make the potential of `H_(2)`- ele

1.	The pressure of `H_(2)` required to make the potential of `H_(2)`- electrode zero in pure water at 298 K isA. `10^(-10)m`B. `10^(-4)atm`C. `10^(-14)atm`D. `10^(-12)atm`
Answer» Correct Answer - C The reduction reaction for `H_(2)`-electrode is `2H^(+)(aq)+2^(-)toH_(2)(g)` `H_(H^(+)//H_(2))^(@)=E_(H^(+)//H_(2))^(@)-(0.0591)/(2)"log"(p_(H_(2)))/([H^(+)]^(2))` In pure water at 298K, `[H^(+)]=10^(-7)M` `therefore0=0-(0.0591)/(2)"log"(p_(H_(2)))/((10^(-7))^(2))` or `"log"(p_(H_(2)))/(10^(-14))=0` or `(p_(H_(2)))/(10^(-14))=1" "(becauselog1=0)` or `p_(H_(2))=10^(-14)atm`

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The pressure of `H_(2)` required to make the potential of `H_(2)`- electrode zero in pure water at 298 K isA. `10^(-10)m`B. `10^(-4)atm`C. `10^(-14)atm`D. `10^(-12)atm`

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