InterviewSolution
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InterviewSolution
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The quadratic equation `2x^(2)-sqrt5x+1=0` has (a) two distinct real roots (b) two equal real roots (c) no real roots (d) more than 2 real roots |
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Answer» Given equation is `2x^(2)-sqrt5x+1=0` Here `a=2,b=sqrt5,c=1` `because"Discriminant D"=b^(2)-4ac` `=(-sqrt5)^(2)-4(2)(1)=5-8=-3lt0` `implies` Given equation has no real root. |
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