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The radius of the `Na^(2+)` is `95p m` and that of `Cl^(-)` ion is `181 p m`. Predict the co`-` ordination number of `Na^(+) :`A. 4B. 6C. 8D. unpredictable |
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Answer» Correct Answer - B `(r_(Na^(+)))/(r_(Cl^(-)))=(95)/(181)=0.524, i.e., ` between `0.414` to `0.732` and thus co`-` ordination no. `=6` |
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