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InterviewSolution
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the rate law for the reaction, 2Cl2O → 2Cl2 + O2 at 200oC is found to be : rate = k[Cl2O]2(a) How would the rate change if [Cl2O] is reduced to one-third of its original value? (b) How should the [Cl2O] be changed in order to double the rate? (c) How would the rate change if [Cl2O] is raised to threefold of its original value? |
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Answer» the rate law for the reaction, 2Cl2O → 2Cl2 + O2 at 200oC is found to be : rate = k[Cl2O]2 (a) How would the rate change if [Cl2O] is reduced to one-third of its original value? (b) How should the [Cl2O] be changed in order to double the rate? (c) How would the rate change if [Cl2O] is raised to threefold of its original value? |
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