The ratio of the number of neutrons present in the two element X and Y is 5:7 and the ratio of mass numbers is 10:13. Element X attains stable octet configuration by losing two elements from the fourth shell. Calculate the number of proteins , electrons and neutrons present in X and Y.

The ratio of the number of neutrons present in the two element X and Y

1.	The ratio of the number of neutrons present in the two element X and Y is 5:7 and the ratio of mass numbers is 10:13. Element X attains stable octet configuration by losing two elements from the fourth shell. Calculate the number of proteins , electrons and neutrons present in X and Y.
Answer» Solution :Element X attains stability by loosing two electrons from `4^(th)` shell, it's atomic NUMBER is 20, element is calcium. `therefore` The mass number of Ca is 40. Let the mass number of Y is a. `therefore(40)/(a)=(10)/(13) implies a =52` `therefore ` Mass number of Y is 52. Number of neutrons in X is 40-20=20 Let the atomic number of Y be n. `therefore` The number of neutrons in Y be 52-b `therefore(20)/(52-b)=(5)/(7)implies 52-b=28implies b=24` `therefore ` Element Y atomic number is 24 and number of neutrons in Y are 28