The resistance of a conductivity cell containing 0.001 M KCl solution at 298 K is 1500 Ω. What is the cell constant if conductivity of 0.001 M KCl solution at 298 K is 0.146 × 10-3 S cm-1?

The resistance of a conductivity cell containing 0.001 M KCl solution

1.	The resistance of a conductivity cell containing 0.001 M KCl solution at 298 K is 1500 Ω. What is the cell constant if conductivity of 0.001 M KCl solution at 298 K is 0.146 × 10-3 S cm-1?
Answer» Concentration = 0.01 Ω R = 1500 Ω G* (cell constant) = ? K (conductivity) = 0.416 × 10^-3 S cm^-1 Since, k = \(\frac { Cellconstant }{ R } \) Cell constant = k × R = 0.146 × 10^-3 × 1500 = 0.219 cm^-1

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The resistance of a conductivity cell containing 0.001 M KCl solution at 298 K is 1500 Ω. What is the cell constant if conductivity of 0.001 M KCl solution at 298 K is 0.146 × 10-3 S cm-1?

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