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The resistance of a conductor is 27Ω. If it is cut into three equal parts and connected in parallel, then its total resistance is​

Answer» <html><body><p>In this <a href="https://interviewquestions.tuteehub.com/tag/case-910082" style="font-weight:bold;" target="_blank" title="Click to know more about CASE">CASE</a>, a wire of uniform thickness with a <a href="https://interviewquestions.tuteehub.com/tag/resistance-1186351" style="font-weight:bold;" target="_blank" title="Click to know more about RESISTANCE">RESISTANCE</a> of 27 is cut into three equal pieces and they are joined in parallel. As we know that the resistance is <a href="https://interviewquestions.tuteehub.com/tag/directly-955045" style="font-weight:bold;" target="_blank" title="Click to know more about DIRECTLY">DIRECTLY</a> proportional to the length of the wire, R∝L, so when the wire is cut into 3, the resistance of the cut wire is reduced to one third of the total resistance. That is, the resistance of each cut wire becomes 27/3= 9 ohms.Now, when these 3 wires are connected in a parallel connection, the total resistance is given as 91+91+91=0.3331=3ohms.Hence, the total resistance is now 3 ohms only.Explanation: <a href="https://interviewquestions.tuteehub.com/tag/mark-555248" style="font-weight:bold;" target="_blank" title="Click to know more about MARK">MARK</a> as brainliest bro</p></body></html>


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