The `S_(N^(1))` reactivity of the following halides will be in the order: (i) `(CH_(3))_(3)C-Br` (ii) `(C_(6)H_(5))CHBr` (iii) `(C_(6)H_(5))_(2)C(CH_(3))Br` (iv) `(CH_(3))_(2)CHBr` (v) `C_(2)H_(5)Br`A. (v) gt (iv) gt (i) gt (ii) gt (iii)B. (ii) gt (iii) gt (v) gt (i) gt (iv)C. (i) gt (iii) gt (v) gt (ii) gt (iv)D. (iii) gt (ii) gt (i) gt (iv) gt (v)

The `S_(N^(1))` reactivity of the following halides will be in the ord

1.	The `S_(N^(1))` reactivity of the following halides will be in the order: (i) `(CH_(3))_(3)C-Br` (ii) `(C_(6)H_(5))CHBr` (iii) `(C_(6)H_(5))_(2)C(CH_(3))Br` (iv) `(CH_(3))_(2)CHBr` (v) `C_(2)H_(5)Br`A. (v) gt (iv) gt (i) gt (ii) gt (iii)B. (ii) gt (iii) gt (v) gt (i) gt (iv)C. (i) gt (iii) gt (v) gt (ii) gt (iv)D. (iii) gt (ii) gt (i) gt (iv) gt (v)
Answer» Correct Answer - D More stable the carbocation more reactive is the alkyl halide in `S_(N^(1))` reaction. Since the stability of the carbocations decreases the order of their reactivity is `(C_(6)H_(5))_(2)overset(+)(C )CH_(3)gt (C_(6)H_(5))_(2)CH^(+)gt(CH_(3))_(3)C^(+)gt(CH_(3))_(2)C_(2)^(+)H_(5)`, hence the reactivity of the alkyl halides decreases in the same order. So (iii) gt (ii) gt (i) gt (iv) gt (v) i.e., (C ) is correct.

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