The Schrondinger equation for hydrogen atom is ψ=14√2π(1a0)32(2−r0a0)e−r0a0, where a0 is Bohr's radius. If the radial node is 2s be at r0. Then, r0 in terms of a0 is given as xa0=r0, value of x is

The Schrondinger equation for hydrogen atom is ψ=14√2π(1a0)32(2�

1.	The Schrondinger equation for hydrogen atom is ψ=14√2π(1a0)32(2−r0a0)e−r0a0, where a0 is Bohr's radius. If the radial node is 2s be at r0. Then, r0 in terms of a0 is given as xa0=r0, value of x is
Answer» The Schrondinger equation for hydrogen atom is $ψ = \frac{1}{4 \sqrt{2 π}} (\frac{1}{a_{0}})^{\frac{3}{2}} (2 - \frac{r_{0}}{a_{0}}) e^{-} \frac{r_{0}}{a_{0}}$ , where $a_{0}$ is Bohr's radius. If the radial node is $2 s$ be at $r_{0}$ . Then, $r_{0}$ in terms of $a_{0}$ is given as $x a_{0} = r_{0}$ , value of $x$ is

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The Schrondinger equation for hydrogen atom is ψ=14√2π(1a0)32(2−r0a0)e−r0a0, where a0 is Bohr's radius. If the radial node is 2s be at r0. Then, r0 in terms of a0 is given as xa0=r0, value of x is

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