1.

The solubility of silver chloride is 1.562 × 10-10 mol dm-3 at 298 K. Find its solubility in g dm-3 at the same temperature.

Answer»

Given : 

Solubility of AgCl = S = 1.562 × 10-10 mol dm-3 

Solubility of AgCl in g dm-3 = ? 

Molar mass of AgCl = M = 143.5 g mol-1 

Solubility in gram per dm3,

= solubility in mol dm-3 × molar mass 

= 1.562 × 10-10 × 143.5 

= 2.241 × 10-5 g dm-3 

∴ Solubility of AgCl = 2.241 × 10-8 g dm-3



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