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    				| 1. | The solubility of silver chloride is 1.562 × 10-10 mol dm-3 at 298 K. Find its solubility in g dm-3 at the same temperature. | 
| Answer» Given : Solubility of AgCl = S = 1.562 × 10-10 mol dm-3 Solubility of AgCl in g dm-3 = ? Molar mass of AgCl = M = 143.5 g mol-1 Solubility in gram per dm3, = solubility in mol dm-3 × molar mass = 1.562 × 10-10 × 143.5 = 2.241 × 10-5 g dm-3 ∴ Solubility of AgCl = 2.241 × 10-8 g dm-3 | |