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The solution which consumes `[H^(+)]` or `[OH^(-)]` or both simultaneously from externally added base in order to give negligible change in `pH`, is known as buffer solution. In general, the solution resists the change in pH. Buffer solution does not mean that there does not occur a pH change in pH. Buffer solution des not mean that there does not occur a pH change at all. It implies the pH change occurs but in neglibible amount. There are two types of buffer (i) Acidic buffer: it is a mixture of weak acid and its salt acid strong base. (ii) Basic buffer : It is a mixture of weak base and its salt with strong acid. To prepare a buffer of `pH 8.26`, amount of `(NH_(4))_(2)OH` solution `[pK_(a)(NH_(4^(+)) = 9.26]`A. `0.05`molB. `0.025` molC. `0.01` molD. `0.005` mol |
Answer» Correct Answer - B `5.74 = 4.74 + "log" (x)/(5 xx 10^(-3))`, calculating `x = 0.02`, hence `[(NH_(4))_(2)SO_(4)]` required `= 0.01` |
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