The Square Of A Two Digit Number Is Divided By Half The Number. After

1.	The Square Of A Two Digit Number Is Divided By Half The Number. After 36 Is Added To The Quotient, This Sum Is Then Divided By 2. The Digits Of The Resulting Number Are The Same As Those In The Original Number, But They Are In Reverse Order. The Ten's Place Of The Original Number Is Equal To Twice The Difference Between Its Digits. What Is The Number?
Answer» Let the number be 10A + B = C now, (C^2/(C/2) + 36)/2= 10B + A or, (2C+36)/2 = 10B + A or C+18=10B+A or, 10A + B + 18 = 10 B + A or, 18=9(B-A), GIVING B-A=2 As PER the question, A=twice the difference between A and B Hence A=22=4 B=2+4=6 The original number is 40 + 6 = 46. Let the number be 10A + B = C now, (C^2/(C/2) + 36)/2= 10B + A or, (2C+36)/2 = 10B + A or C+18=10B+A or, 10A + B + 18 = 10 B + A or, 18=9(B-A), giving B-A=2 As per the question, A=twice the difference between A and B Hence A=22=4 B=2+4=6 The original number is 40 + 6 = 46.

The Square Of A Two Digit Number Is Divided By Half The Number. After 36 Is Added To The Quotient, This Sum Is Then Divided By 2. The Digits Of The Resulting Number Are The Same As Those In The Original Number, But They Are In Reverse Order. The Ten's Place Of The Original Number Is Equal To Twice The Difference Between Its Digits. What Is The Number?

Answer»

Let the number be 10A + B = C

now, (C^2/(C/2) + 36)/2= 10B + A

or, (2C+36)/2 = 10B + A

or C+18=10B+A

or, 10A + B + 18 = 10 B + A

or, 18=9(B-A), GIVING B-A=2

As PER the question, A=twice the difference between A and B

Hence A=2*2=4

B=2+4=6

The original number is 40 + 6 = 46.