InterviewSolution
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InterviewSolution
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The stability of carbanions in the following (i) `RC-=overset(-)overset(..)C` , (ii) (iii) `R_(2)C=overset(-)overset(..)CH` , (iv) `R_(3)C-overset(-)overset(..)CH_(2)` is in the orderA. `(iv)gt(ii)gt(iii)gt(i)`B. `(i)gt(iii)gt(ii)gt(iv)`C. `(i)gt(ii)gt(iii)gt(iv)`D. `(ii)gt(iii)gt(iv)gt(i).` |
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Answer» Correct Answer - C The stability of carbanion decreases as the electronegativity of carbon carrying the -ve charge decreases or the hybridization of the carbon carrying the -ve charge changes from `sp-sp^(2)-sp^(3)`. Hence `RCequivC^(-)` (l) is the most stable while `R_(3)C-CH_(2)^(-)` (IV) is the least stable carbon anion. The carbon atom carrying the -ve charge in both `C_(6)H_(5)^(-)" and "RC = overset(-)CH` is `sp^(2)` hybridized. Out of these two `RC= CH^(-)` (iii) is less stable than `C_(6)H_(5)^(-)` (II) due to two R groups. `therefore` over all stability decreases in the order `(i)gt(ii)gt(iii)gt(iv)` |
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