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The standard electrode potential for the following reaction is `-0.57` V. What is the potential at pH=12.0 ? `TeO_(3)^(2-)(aq,1M)+3H_(2)O(l)+4e^(-)toTe(s)+6OH^(-)(aq)`A. `-017 V`B. `+0.21 V`C. `-0.39 V`D. ``+1.95 V` |
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Answer» Correct Answer - C |
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