1.

The temperature coefficient of resistance for two material A and B are `0.0031^(@)C` and `0.0068^(@)C^(-1)` respectively .Two resistance `R_(1) and R_(2)` made from material A and B respectively . Have resistance of `200 Omega` and `100 Omega` at `0^(@)C`. Show as a diagram the colour cube of a carbon resistance that would have a resistance equal to the series combination of `r_(1) and R_(2)` at a temperature of `100^(@)C` (Neglect the ring corresponding to the tolerance of the carbon resistor)

Answer» `R_(1)("at "100^(@)C)=R_(1)(0^@C)[1+alpha.t]`
`=200(1+.0031xx100)`
`=200(1.31)=262Omega`
`R_(2)("at "100^(@)C)=R_(2)(0^(@)C)[+alpha.t]`
`=100.[1+.0068xx100]`
`=100(1.68)=168Omega`
`R_(1)+R_(2)=262+168=430Omega`
Yellow Orange Brown.


Discussion

No Comment Found

Related InterviewSolutions