The temperature of 20 g of oxygen gas is raised from 50^(@)C to 100^(@)C. (i) At constant volume. Find out the amount of heat supplied and the rise in internalenergy in case. Given , R = 2 cal cdot mol^(-1) cdot K^(-1) , for oxygen, c_(v) = 0.155 cal cdot g^(-1) cdot^(@)C^(-1).

The temperature of 20 g of oxygen gas is raised from 50^(@)C to 100^(@

1.	The temperature of 20 g of oxygen gas is raised from 50^(@)C to 100^(@)C. (i) At constant volume. Find out the amount of heat supplied and the rise in internalenergy in case. Given , R = 2 cal cdot mol^(-1) cdot K^(-1) , for oxygen, c_(v) = 0.155 cal cdot g^(-1) cdot^(@)C^(-1).
Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/heat-21102" style="font-weight:bold;" target="_blank" title="Click to know more about HEAT">HEAT</a> supplied at constant <a href="https://interviewquestions.tuteehub.com/tag/volume-728707" style="font-weight:bold;" target="_blank" title="Click to know more about VOLUME">VOLUME</a>, <br/> `Q_(v) = mc_(v) (t_(f) - t_(i))` <br/> `=20 xx 0.155 xx (100-50) = 155 cal` <br/> Work done, W = 0 <br/> So, rise in internal <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> , <br/>`U_(f) - U_(i) = <a href="https://interviewquestions.tuteehub.com/tag/q-609558" style="font-weight:bold;" target="_blank" title="Click to know more about Q">Q</a> - W = 155 - 0 = 155 cal` <br/> `= 155 xx 4.2 J = 651 J`.</body></html>