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The time period of oscillation of a body is given by `T=2pisqrt((mgA)/(K))` K: Represents the kinetic energy, m mass, g acceleration due to gravity and A is unknown If `[A]=M^(x)L^(y)T^(z)`, then what is the value of x+y+z?A. 3B. 2C. 1D. 5 |
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Answer» Correct Answer - A `[T]=[((mgA)/(K))^(1//2)]=[(mgA)/((mv^(2)))]^(1//2)=[(A)/(vT)]^(1//2)=[(A)/(L)]^(1//2)` `implies[A]=[M^(0)LT^(2)]implies[M^(x)L^(y)T^(z)]=[M^(0)LT^(2)]` `impliesx=0,y=1,z=2impliesx+y+z=3` |
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