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The total number of alcohols (including stereoisomers) possible with the formula `C_(5)H_(12)O` isA. `8`B. `10`C. `11`D. `9` |
Answer» Correct Answer - C Draw the five carbon atoms in sequence and then positions the `OH` giving three structural isomers. `underset(underset(underset("Diethylcarbinol")(n-"Pentylalchol"))(Pentan-1-ol(1^(@))))(CH_(3)CH_(2)CH_(2)CH_(2)CH_(2)OH) underset(C^(2)"is chiral"(+,-))underset("methylpropylcarbinol")underset("Pentan-2-ol(2^(@)))(CH_(3)overset(**)CH(OH)CH_(2)CH_(2)CH)` `underset("Diethylcarbinol")underset("Pentan-3-ol")(CH_(3)CH_(2)CH(OH)CH_(2)CH_(3))` Draw four carbon atoms in sequence and then position `CH_(3)` and `OH` to give four structural isomers. `underset("Isobutylcarbinol")underset(3-"Methylbutan-1-ol"(1^(@)))(CH_(3)overset(CH_(3))overset(|)(CH)CH_(2)CH_(2)OH) underset(C^(2) "is chiral"(+,-))underset("Methylisopropylcarbinol")underset(3-"Methylbutane-2-ol(2^(@)))(CH_(3)overset(CH_(3))overset(|)(CH)underset(OH)underset(|)overset(**)(CH)CH_(3))` `CH_(3) underset("Dimethylethylcarbinol") underset (t -"Pentylalcohol") underset(3-"Methylbutan"-2-ol(3^(@))) (underset(OH)underset(|) overset(CH_(3))overset(|)(C)CH_(2)CH_(3)) , underset("C^(2) is chiral(+ ,-)") underset("Sec-Butylcarbinal") underset(2-"Methylbutan"-1-ol(1^(@)))(HOCH_(2)overset(CH_(3))overset(|**)(CH)CH_(2)CH_(3))` With three sequential carbon atoms, there is just one structural isomer : `CH_(3) - underset(t-"Butylcarbinol") underset("Neopentylalcohol") underset(2 ,2-"Dimethylpropan"-1-ol(1^(@)))(underset(CH_(3)) underset(|) overset(CH_(3)) overset(|)(C)-CH_(2)-OH)` Thus, a total of eleven alcohols (including stereoisomers) is possible |
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