InterviewSolution
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InterviewSolution
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The unit cube length for `LiCl` (`NaCl` structure) is `5.14 Å`. Assuming anion-anion contact, calculate the ionic radius for chloride ion. |
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Answer» Interionic distance of `LiCl` `= (5.14)/(2) = 2.57 Å` `:. BC = sqrt(AB^(2) + AC^(2)) = sqrt((2.57)^(2) + (2.57)^(2)) = 3.63` Radius of `Cl^(Θ)` ion `= (1)/(2) xx 3.63 = 1.81 Å` |
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