1.

The `v-s` and `v^(2)-s` graph are given for two particles. Find the accelerations of the particles at `s=0`. .

Answer» `a_(1)=(vdv)/(ds)`, where `v=20 m s^(-1)` (at s=0)
and `(dv)/(ds)=-(2)/(5)=(a_(1))/(v) =a_(1)/(20)`
Then, `a_(1) =-8 m s^(-2)`
`a_(2)=(1)/(2)(d(v^(2)))/(ds)`, where `(d(v^(2)))/(ds) =-(2)/(5)`
Then, `a_(2)=-0.2 m s^(-2)`.


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