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The valancy of carbons is generally `4`, but its oxidation state may be `-4, -2, 0, +2, -1`, etc. In the compounds containing `C, H`, and `O`, the oxidation number of `C` is calculated as Oxidation number of `C= (2n_(O)-n_(H))/(n_(C ))` Where `n_(O), n_(H)` and `n_(C )` are the numbers of oxygen, hydrogen, and carbons, atoms, respectively. In which of the following compounds is the valency of `C` two?A. KetenesB. AlkenesC. AllenesD. Carbenes |
Answer» Correct Answer - D a. `H_(2)C=C=O`(Ketenes)(Valency of `C=4`) b. `R_(2)(C )=CR_(2)`(alkenes) (Valency of `C=4`) c. `H_(2)C=C=CH_(2)`(Allenes) (Valency of `C=4)` d. `:CH_(2)` (Carbenes) (Valency of `C=2`) |
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