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The value of k for which the pair of linear equations 4x + 6y – 1 = 0 and 2x + ky – 7 = 0 represents parallel lines is (1) k = 3 (2) k = 2 (3) k = 4 (4) k = -3 |
Answer» (1) k = 3 4x + 6y = 1 6y = -4x + 1 y = \(\frac{-4}{6}x+\frac{1}{6}\) … (1) 2x + ky – 7 = 0 ky = -2x + 7 y = \(\frac{-2}{k}x+\frac{7}{k}\) ... (2) Since the lines (1) and (2) parallel m1 = m2 \(\frac{-4}{6}=\frac{-2}{k}\) k = -2 x \(\frac{-6}{4}\) = 3 |
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