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The value of the reaction quotient, Q, for the cell: `Ni(s)|Ni^(2+)(0.9M)||Cl^(-)(0.40M)|Cl_(2)(g0.10"atm"),Pt(s)` isA. `1.3xx10^(-1)`B. `8.0xx10^(-2)`C. `3.0xx10^(-1)`D. `3.0xx10^(-2)` |
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Answer» Correct Answer - c The half cell reaction and overall recation are `Ni rarrNi^(2+)+2e^(-)` `Cl_(2)+2e^(-)rarr2Cl^(-)` `NirarrNi^(2+)+2Cl^(-)` `therefore Q([Ni^(2+)][Cl^(-)](2))/([pCl_(2)])` `=(0.19xx(0.4)^(4))/(0.1)=0.304` `=3.04xx10^(-1)` |
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